Bowling Ball (Solution)
Weight will be proportional to volume (assuming same density). Let’s just set up a ratio.
\[\frac{12^3}{8^3} = \frac{x}{8} \\ \frac{3^3}{2^3} = \frac{x}{8} \\ 3^3 = x \\ x = 27\]Weight will be proportional to volume (assuming same density). Let’s just set up a ratio.
\[\frac{12^3}{8^3} = \frac{x}{8} \\ \frac{3^3}{2^3} = \frac{x}{8} \\ 3^3 = x \\ x = 27\]